Question

WILL MARK BRAINLIEST. Look at the circuit below. What is the voltage between points C and D?


A. 6 V

B. 0 V

C. 1.5 V

D. 3 V

Answer 1

Since two identical bulbs are connected in this circuit in series combination

So here same current will flow into the circuit

So here we can say

$V = V_1 + V_2$

$V = 3 volts$

also we know that

$V_1 = iR_1$

$V_2 = iR_2$

also it is given that bulbs are identical so we have

$V_1 = V_2$

as we have

$R_1 = R_2$

so now we can say

$V = 2V_{CD}$

$3 = 2V_{CD}$

$V_{CD} = 1.5 Volts$

so here voltage across C and D is 1.5 volts

Answer 2

The hard way:

-- The total resistance in the series circuit is 120 ohms.

-- The current in the circuit is (voltage)/(resistance) = 3/60 = 0.025 A

-- The resistance between C and D is 60 ohms.

-- The voltage across a resistance is (current) x (resistance) = (0.025 x 60) = 1.5 volts. (C)

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The easy way:

-- In a series circuit, the total voltage of the power source divides among the circuit's components in proportion to their resistances.

-- Since the bulbs have equal resistances, each one will have 1/2 of the battery voltage across it.

-- (1/2) of (3 volts) = 1.5 volts (C)