Given: ABCD is a ∥-gram; DE ∩ AB =F
Prove: △ADF∼△CDE
![Given ABCD is a gram DE AB F Prove ADFCDE class=](https://us-static.z-dn.net/files/d39/a643544e1553092c1d3956607892d239.png)
Answer:
By AA similarity
Step-by-step explanation:
We have been given that ABCD is a parallelogram
So, by the property of parallelogram AB ||CD and FD is cutting the line BC
Hence, FD is transverse line. In transverse line alternate angles are equal.
Therefore, ∠AFD=∠EDC (alternate interior angles)
And ∠FAD=∠ECD (opposite angles in parallelogram)
Therefore, by AA similarity △ADF∼△CDE