Question

Please help!!!
Find the correlation coefficient of the data. Round to the nearest hundredth.

Answer 1

Answer:

r ≈ 0.98

Step-by-step explanation:

The correlation coefficient is easily calculated by almost any scientific or graphing calculator, or by a spreadsheet. It is mainly a matter of data entry and invoking the appropriate function. Here, the correlation coefficient is computed as about 0.97716, or 0.98 when rounded to the nearest hundredth.

Answer 2

Answer:

The correlation coefficient is 0.0002273427

Step-by-step explanation:

Given the data of heart rate and we have to find the correlation coefficient which can be calculated as

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^{2}-(\sum x)^{2} ] [n\sum y^{2}-(\sum y)^{2} ] }} }$

       = $=\frac{12(7949)-68(1341)}{\sqrt{[12(430)-4624][12(152729)-1798281]} }$

       = $\frac{4200}{(536)(34467)}$

       = 0.0002273427