[tex]f(x)=25-x^2,\ g(x)=x+5\\\\\dfrac{f(x)}{g(x)}\cdot x=\dfrac{25-x^2}{x+5}\cdot x=\dfrac{x(25-x^2)}{x+5}\\\\\text{Domain:}\ x\neq-5\\\\25-x^2=5^2-x^2=(5-x)(5+x)\\\\\dfrac{f(x)}{g(x)}\cdot x=\dfrac{x(5-x)(5+x)}{x+5}=x(5-x)=5x-x^2\to\text{simplified form}[/tex]
