Question

The normal boiling point of 2-propanol, (CH3)2CHOH, is 83 ºC, while that of acetone, (CH3)2C=O, is 56 ºC. What is the principal reason for the greater boiling point of 2- propanol?

(A) The O–H bond in 2-propanol is stronger than the C–H bonds in acetone.

(B) 2-Propanol experiences greater London dispersion forces than acetone.

(C) 2-Propanol experiences stronger dipole-dipole interactions than acetone.

(D) 2-Propanol experiences stronger hydrogen bonding than acetone.

Answer 1

The answer is: (D) 2-Propanol experiences stronger hydrogen bonding than acetone.

2- propanol has greater boiling point, because hydrogen bonds between 2-propanol molecules, more energy is required to breake those bonds.

Hydrogen bond is an electrostatic attraction between two polar groups that occurs when a hydrogen atom (H), covalently bound to a highly electronegative atom such as flourine (F), oxygen (O) and nitrogen (N) atoms.

In molecule of 2-propanol there are hydrogen forces between negatively charged oxygen from one molecule of 2-propanol and positively charger hydrogen of another molecule of 2-propanol.

2-propanol is alcohol and acetone is ketone, both are organic compounds.