Question

Given: 1/3 x + y = 15. Which if the following are ordered pairs of this equation?

{(-3, 14), (0, 15), (3, 16)}
{(-3, 16), (0, 15), (3, 14)}
{(16, -3), (15, 0), (14, 3)}

Answer 1

The correct answer is the second answer----{(-3, 16), (0, 15), (3, 14)}

Answer 2

Answer:

Option B - {(-3, 16), (0, 15), (3, 14)}

Step-by-step explanation:

Given : Equation $\frac{1}{3}x+y=15$.

To find : Which if the following are ordered pairs of this equation?

Solution :

Re-write the equation in linear equation format,

$y=-\frac{1}{3}x+15$

Taking point, (-3,16)

We substitute x=-3,

$y=-\frac{1}{3}(-3)+15$

$y=1+15$

$y=16$

It is true.

Taking point, (0,15)

We substitute x=0,

$y=-\frac{1}{3}(0)+15$

$y=0+15$

$y=15$

It is true.

Taking point, (3,14)

We substitute x=3,

$y=-\frac{1}{3}(3)+15$

$y=-1+15$

$y=14$

It is true.

Therefore, the ordered pairs are {(-3, 16), (0, 15), (3, 14)}.

So, option B is correct.