Which expression is equivalent to

Answer:
[tex]22x^2-x+17[/tex]
Step-by-step explanation:
We have
[tex]10-(2x^3+11x^2-2x-35) \div (x+5)+6(4x^2).[/tex]
We must simplify this in the order specified by BIDMAS: brackets, indices, division, multiplication, addition, subtraction.
Because there is nothing in brackets which can be simplified and there are no indices (powers) either our first step is to simplify the division. That is, to simplify [tex](2x^3+11x^2-2x-35) \div (x+5).[/tex]
My favourite way to solve this is by "reverse-factorisation." Observe that if
[tex](2x^3+11x^2-2x-35) \div (x+5) = y[/tex] then [tex]y(x+5) = (2x^3+11x^2-2x-35)[/tex]. That means we are looking for a polynomial y that makes that equation true.
[tex]2x^3+11x^2-2x-35 = (\ \ \ \ \ \ )(x+5)[/tex] where y is the "blank" bracket we need to (and can) fill in. Imagine we are expanding the brackets, the first terms multiplied together must give [tex]2x^3[/tex] and we know one of them is [tex]x[/tex] which means the missing term (at the start of the y bracket) must be [tex]2x^2[/tex]. But if [tex]2x^2[/tex] is in y then after we have multiplied the first terms we have to multiply the [tex]2x^2[/tex] by the next term in [tex](x+5)[/tex], that is the [tex]+5[/tex] term. That is [tex]2x^2 \times 5[/tex] which is [tex]10x^2[/tex]. We want it to be [tex]11x^2[/tex] however so we need to add one more [tex]x^2[/tex] to the left hand side. What can we add into the empty y bracket to be multiplied by [tex](x+5)[/tex] to give [tex]x^2[/tex]? We add another [tex]x[/tex] and multiply out by the [tex](x+5)[/tex] bracket to see we achieve the required [tex]11x^2[/tex] but also obtain an "extra" [tex]5x[/tex] by multiplying the new [tex]x[/tex] by the [tex]5.[/tex] Repeat the process one final time, we have +5x we need -2x so add [tex]-7[/tex] to the bracket. When multiplied out, this yields [tex]-7x[/tex] which brings us to the required [tex]-2x[/tex] and also when multiplied by the +5 yields -35. This completes the reverse factorisation and we see the missing y bracket is [tex](2x^2+x-7)[/tex]. Hence this is the result of the division [tex](2x^3+11x^2-2x-35) \div (x+5).[/tex]
The expression then becomes [tex]10-(2x^2+x-7)+6(4x^2)[/tex]. To multiply out the last bracket is simple and we see the expression is equivalent to [tex]10-(2x^2+x-7)+24x^2[/tex]. Finally notice the minus sign is in front of a bracket which means the minus applies to all terms within the bracket so flipping the signs inside the bracket shows us the expression is [tex]10-2x^2-x+7+24x^2 = 22x^2-x+17[/tex].
Most of the hard work came from the polynomial division. I hope I explained it clearly enough, if not, leave message in the comments and I'll try again. If you don't like my "reverse-factorisation" there are other methods to do polynomial division which I can try demonstrate but they are difficult to show on Brainly.