Question

The molarity (M) of an aqueous solution containing 15.6 g of sucrose, C12H22O11, in 65.5 mL of solution is:

6.96 x 10–4 M.

2.47 x 10–2 M.

0.696 M.

1.33 M.

Answer 1

the molecularity of C12H22O11 is = 12x12+22x1+16x11 = 342 g/mol

molarity (M) = moles / V. solution

moles = mass / 342 = 15,6/342 = 0,0456 moles

=> molarity (M) = 0,0456/0,0655 = 0,696 M