Respuesta :

Answer:

(-1, -1)

Step-by-step explanation:

Rotating the point (-1, -1) about the origin at -90° will be a 90 degree clockwise rotation.  This will map switch the x- and y-coordinates and negate the x-coordinate:

(x, y)→(y, -x)

(-1, -1) → (-1, 1)

Following this with a 90 degree counter-clockwise rotation will map

(x, y)→(-y, x)

(-1, 1)→(-1, -1)

This is the same point we started with.  Thinking about this logically, if we rotate something 90 degrees clockwise and then follow that with a 90 degree counter-clockwise rotation will put the object back in its original position.

Answer:

The correct option is 3.

Step-by-step explanation:

The coordinates of point P are (4,3).

We have to find the value of

[tex]R_{p,90}\circ R_{o,-90}:(-1,-1)[/tex]

The operations area operated from right to left it means first we have to apply

[tex]R_{o,-90}[/tex], then [tex]R_{p,90}[/tex].

[tex]R_{o,-90}[/tex] means rotation 90 degree clockwise about the origin, it is defined as

[tex](x,y)\rightarrrow (y,-x)[/tex]

[tex](-1,-1)=(-1,1)[/tex]

[tex]R_{p,90}[/tex] means rotation 90 degree counter clockwise about the the point P, it is defined as

[tex](x,y)\rightarrrow (-(y-3)+4,(x-4)+3)[/tex]

[tex](x,y)\rightarrrow (-y+7,x-1)[/tex]

[tex](-1,1)\rightarrrow (-1+7,-1-1)[/tex]

[tex](-1,1)\rightarrrow (6,-2)[/tex]

Therefore the coordinates of image are (6,-2). Option 3 is correct.

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