The quick way would be to use the 68-95-99.7 rule. Notice that 825 = 750 + 75, so that 825 is one standard deviation away from the mean. The rule says that approximately 68% of a normal distribution lies within one standard deviation of the mean (in the interval [750 - 75, 750 + 75] = [675, 825]), so about 34% would lie within one standard deviation to the right of the mean.
The longer but more accurate way would be to compute the probability:
[tex]P(750\le X\le825)=P\left(\dfrac{750-750}{75}\le\dfrac{X-750}{75}\le\dfrac{825-750}{75}\right)[/tex]
[tex]=P(0\le Z\le1)[/tex]
where [tex]Z[/tex] is a random variable following the standard normal distribution with mean 0 and standard deviation 1. We find
[tex]P(0\le Z\le1)=P(Z\le1)-P(Z\le0)\approx0.8413-0.5=0.3413=34.13\%[/tex]
as expected.
Answer 34%
Step-by-step explanation:
LammettHash is right just take it as a whole number (for those of you using acellus)
