the center of a circle is at (-2, - 7) and its radius is 36 what is equation of the circle

A, (x-2)^2 +(y, - 7)^2 = 6

B, (x+2)^2 +(y, + 7)^2 = 6

C, (x-2)^2 +(y, - 7)^2 = 1296

D, (x+2)^2 +(y, + 7)^2 = 1296

Respuesta :

ANSWER

The required equation is,

[tex] {(x + 2)}^{2} + {(y + 7)}^{2} = 1296[/tex]

EXPLANATION

We want to find the equation of the circle given center [tex](-2,-7) [/tex]

and radius [tex]36[/tex] units.


The equation of a circle given the radius,
[tex]r[/tex]
and center
[tex](a,b) [/tex]

is given by the formula,

[tex] {(x - a)}^{2} + {(y - b)}^{2} = {r}^{2} [/tex]

We substitute,

[tex]a=-2,b=-7, r=36 [/tex]

to obtain,

[tex] {(x - - 2)}^{2} + {(y - - 7)}^{2} = {(36)}^{2} [/tex]

This will simplify to give us,

[tex] {(x + 2)}^{2} + {(y + 7)}^{2} = 1296[/tex]

The correct answer is D.
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