Question

here are the first four terms of a sequence. 1/2 4/3 9/4 16/5. find the nth term of this sequence.

Answer 1

Answer:n^2/(n+1)

Step-by-step explanation:

n=1

1^2/(1+1) = 1/2

n=2

2^2/(2+1) = 4/3

n=3

3^2/(3+1) = 9/4

Answer 2

Answer:

n^2/(n + 1)

Step-by-step explanation:

The numerators are the squares of the sequence numbers 1^1  2^2  3^2....

The denominators are the  sequence numbers + 1, so the nth term is

n^2/(n + 1).