Question

Use the figure below to answer the question that follows:


What must be given to prove that ΔBIJ ~ ΔBDF?


∠BIJ ≅ ∠BFD


∠BGH ≅ ∠BJI

Answer 1

Answer:

$\angle BIJ\cong \angle BFD$

Step-by-step explanation:

Since,  In triangles BIJ and BDF,

$\angle IBJ\cong \angle FBD$  (Reflexive angles)

If $\angle BIJ \cong \angle BFD$  is given.

Then by AA similarity postulate,

$\triangle BIJ\sim\triangle BFD$

But,   $\angle BGH\cong \angle BJI$  is given

We can not conclude that Triangles BIJ and BFD are similar.

Thus, First Option is correct.

Answer 2

Answer:

Step-by-step explanation: