Answer:
The given sequence is neither arithmetic not geometric.
Step-by-step explanation:
A sequence is in arithmetic if it has a common difference.
i.e., a sequence a, b, c is in arithmetic if
b - a = c - b
Let's check if the given sequence is in arithmetic.
[tex]\frac{4}{3} -\frac{4}{9} =\frac{12}{9} -\frac{4}{9}[/tex]
[tex]= \frac{8}{9}[/tex]
[tex]4-\frac{4}{3} =\frac{12-4}{3}[/tex]
[tex]=\frac{8}{3}[/tex]
So, [tex]\frac{4}{3} -\frac{4}{9} \neq 4-\frac{4}{3}[/tex]
Hence, the given sequence is not arithmetic.
Let's check if the given sequence is in geometric.
A sequence is in geometric if it has a common ratio.
i.e., a sequence a, b, c is in geometric if
[tex]\frac{b}{a} =\frac{c}{b}[/tex]
[tex]\frac{4/3}{4/9} =\frac{4}{3} (\frac{9}{4} )[/tex]
= 3
[tex]\frac{4}{4/3} =4(\frac{3}{4} )[/tex]
= 3
Clearly, [tex]\frac{12}{4} =\frac{36}{12} =3[/tex]
But, [tex]\frac{0}{36} =0[/tex]
Therefore, the given sequence is not in geometric.
Hence, the given sequence is neither arithmetic not geometric.