Question

The polynomial x^3+8 is equal to

Answer 1

Answer:

(x + 2)(x² - 2x + 4)

Step-by-step explanation:

x³ + 8 ← is a sum of cubes, which factors in general as

• a³ + b³ = (a + b)(a² - ab + b²)

x³ = (x)³ ⇒ a = x and 8 = 2³ ⇒ b = 2

x³ + 8 = (x + 2)(x² - 2x + 4) ← in factored form

Answer 2

Answer:

$x^{3} +8=(x+2)(x^{2} -2x+4)$

Step-by-step explanation:

The binomial can be factored by the binomial form by trinomial. This binomial is a sum of cubes, whose general form presents the following result.

$(x^{3} +y^{3} )=(x+y)(x^{2} -xy+y^{2} )$

Substituting the values ​​of x and y we will have

$x^{3} =x^{3} ;     y^{3} =8$

Obtaining the cubic roots of each variable

$x=x; y=2$

So

$x^{3} +8=(x+2)(x^{2} -2x+4)$