Question

Compute the following 8c8

Answer 1

Answer:

1

Step-by-step explanation:

using the definition of n$C_{r}$

= $\frac{n!}{r!(n-r)!}$

where n! = n(n - 1)(n - 2)........ × 3 × 2 × 1

note that 0! = 1

8 $C_{8}$ = $\frac{8!}{8!(0!)}$= 1 ← cancel 8!