Which of the following equations is perpendicular to y = 2x + 5 and passes through the point (4 , 6)? A. y = – 1 2x + 8 B. y = 2x + 8 C. y = – 1 2x – 2 D. y = 2x – 2

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Answer:

The equation would be y = -1/2x + 8

Step-by-step explanation:

To find the equation of the line, we start by find the slope. Perpendicular slopes have opposite and reciprocal slopes. since the original slope is 2, then the perpendicular slope is -1/2.

Now, using the point and the slope in point-slope form, we can find the equation.

y - y1 = m(x - x1)

y - 6 = -1/2(x - 4)

y - 6 = -1/2x + 2

y = -1/2x + 8


The equations that is perpendicular to y = 2x + 5 and passes through the point (4 , 6) is y = - 1/2 x + 8

For an equation to be perpendicular to the another line equation the product of there slope will be negative one. Therefore,

  • m₁m₂ = -1

Therefore, the slope of  y = 2x + 5  is 2. The equation should have the following slope:

2m₂ = - 1

m₂ = -1 / 2

A linear equation is represented as follows:

  • y = mx + b

m = slope

b = y-intercept

Therefore,

let use the point  (4 , 6) to find b

6 = - 1/2 (4) + b

6 = -2 + b

b = 6 + 2

b = 8

The equation will be as follows:

y = - 1/2 x + 8

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