Question

write a quadratic equation in standard form (with integer coefficients) that has roots: 2 and -5?

Answer 1

Answer:

y = x^2 +3x-10

Step-by-step explanation:

If we know the roots of a quadratic function, we know that

y = (x -a) (x-b)  where a and b are the roots

y = (x-2 ) (x--5)

y = (x-2)(x+5)

We need to foil this out to get this in standard form of ax^2 + bx+c

FOIL  (x-2) (x+5)

First x*x:  x^2

outer : 5*x = 5x

inner:  -2x  = -2x

last :  -2*5  = -10

Add them up

x^2 +5x-2x-10

x^2 +3x-10