Question

i dont understand this help me :( What is the equation of a line with a slope of ​3​ and a point (3, 1) on the line?

Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.

Answer 1

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=3(x-3) \\\\\\ y-1=3x-9\implies y=3x-8$