Respuesta :

Let the direction are given as follows

[tex]+x = east[/tex]

[tex]-x = west[/tex]

[tex]+y = North[/tex]

[tex]-y = South[/tex]

now for the above displacement

it moves east for 5 m so it is

[tex]x_1 = 5[/tex]

then goes north for 3 m

[tex]y_1 = 3[/tex]

then goes west for 2 m

[tex]x_2 = -2 m[/tex]

now total displacement in East or x direction

[tex]x = x_1 + x_2 = 5 - 2 = 3m[/tex]

total displacement in North of Y direction

[tex]y = 3m[/tex]

so final coordinates are

[tex]x = 3, y = 3[/tex]

Part b)

position vector is given as

[tex]r = x\hat i + y\hat j[/tex]

[tex]r = 3\hat i + 3\hat j[/tex]

so the magnitude of the vector is given as

[tex]|r| = \sqrt{3^2 + 3^2}[/tex]

[tex]|r| = 3\sqrt3[/tex]