Question

Solve exponential equation
1/16=64^4x-3

Answer 1

Answer: assuming that this was your equation;

$\frac{1}{16} =64^{4x-3}$

You answer is x= 7/12

Step-by-step explanation:

First, rewrite 1/16 as 2^-4 and 64^4x-3 as 2^24x-18

This will leave you with;$2^{-4} =2^{24x-18}$

Since bases are the same, set the exponents equal (eliminate the 2’s);

-4=24x-18

Move 24x to the left to get; -24x-4=-18

Move constant to the right to get -24x=-18+4

Add 4 to -18 to get; -24x=-14

Divide both sides by -24 to get you final answer for x which is 7/12

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Answer 2

The required value of exponential equation is x =  $\frac{7}{12}$.

Given that,

Exponential equation; $\frac{1}{16} = 64^{4x-3}$

We have to determine,

The value of x.

According to the question,

To obtain the value of x by solving the exponential equation follow all the steps given below.

Exponential equation;

$\dfrac{1}{16} = 64^{4x-3}$

Then,

$\dfrac{1}{16} = 64^{4x-3}\\\\\dfrac{1}{2^{4}} = 2^{6(4x-3)}\\\\2^{-4} = 2^{24x-18}$

Since, bases are the same, set the exponents equation,

Then,

Equating the power of exponential equation,

$-4 = 24x-18\\\\24x = -4+18\\\\24x = 14\\\\x = \dfrac{14}{24}\\\\x = \dfrac{7}{12}$

Hence, The required value of exponential equation is $\frac{7}{12}$.

To know more about Exponential function click the link given below.

https://brainly.com/question/20912064