Question

The admission fee at a county fair is $2 for children and $4 dollars for adults. Suppose that on the last day, 1600 people enter the fair and $5000 is collected. Choose the two equations that can be solved as a system of equations to determine how many children and how many adults attended the fair.

1.) a-c=1600
2.) 4a+2c=5000
3.) 4a-2c=5000
4.) a+c=1600

Answer 1

Answer:

2500 children and 625 adults could have attended on this day.

Step-by-step explanation:

5000 divided by 2 is 2500, so 5000 - 2500 = 2500

2500 divided by 4 is 625.

--Emilie Xx

Answer 2

The two equation which are required to know the number of children and student attended the fair are a+c=1600 and 4a+2c=5000. Option 2 and 4 are correct.

What is a system of equation?

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

Let c is the number of children attended the fair and a is the number of adults attended the fair. The total number of people attended the fair is 1600. Thus,

a+c=1600

The fee of admission at a county fair is $2 for children and $4 dollars for adults and total $5000 is collected. Thus,

4a+2c=5000

Hence, the two equation which are required to know the number of children and student attended the fair are a+c=1600 and 4a+2c=5000. Option 2 and 4 are correct.

Learn more about the system of equations here;

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