The equation of a circle is (x−11)2+(y−9)2=225 .
What is the center of the circle?
![The equation of a circle is x112y92225 What is the center of the circle class=](https://us-static.z-dn.net/files/db1/5adb9b546299519db89e796efae9115a.png)
Answer:
(11,9)
Step-by-step explanation:
If a circle is given by its equation [tex](x-a)^2+(y-b)^2=r^2,[/tex] then coordinates of the center are [tex](a,b)[/tex] and radius is r.
In your case, for the circle with equation [tex](x-11)^2+(y-9)^2=225,[/tex] you can state that coordinates of the center are (11,9) and radius is 15.