Question

Find the values for "a" and "b" that would make the equality true. 7(ay^2+by−3)=14y^2−7y−21

Answer 1

Answer:

a = 2 and b = - 1

Step-by-step explanation:

distribute the left side of the equation and compare the like terms with terms on the right side

7ay² + 7by - 21

compare the coefficients of like terms with 14y² - 7y - 21

7a = 14 ⇒ a = 2

7b = - 7 ⇒ b = - 1

Answer 2

The value of a and b  from the given equation is 2 and -1 respectively;

Given the equation $7(ay^2+by-3)=14y^2-7y-21$

In order to get the value of a and b that will make the equality equation true, we will have to factorize first;

$7(ay^2+by-3)=14y^2-7y-21\\7ay^2+7by-21=14y^2-7y-21$

Next is to compare both sides to get the unknown value

$7ay^2=14y^2\\7a=14\\a=\frac{14}{7}\\a =2$

Get the value of "b"

$7by=-7y\\7b=-7b\\b=\frac{-7}{7}\\b=-1$

Hence the value of a and b  from the given equation is 2 and -1 respectively;

Learn more here: https://brainly.com/question/14341790