Question

If f(x)=6x^2-3 and f(x)=3 then what is the value of x

Answer 1

$f(x)=6x^2-3,\ f(x)=3\\\\\text{The equation}\\\\6x^2-3=3\qquad\text{add 3 to both sides}\\\\6x^2=6\qquad\text{divide both sides by 6}\\\\x^2=1\to x=\pm\sqrt1\\\\\boxed{x=-1\ \vee\ x=1}$