Question

A worker pushes a crate horizontally across a warehouse floor with a force of 245 N at an angle of 55 degrees below the horizontal. How much of the worker’s force is not used to move the crate? (1 point)

Answer 1

Horizontal component of force is used to find out the work done

$W = Fdcos\theta$

so we can say the work done as

$W = (Fcos\theta)d$

so here the vertical component of force is not used to find out the work done

so here it would be

$F_y = Fsin\theta$

$F_y = 245sin55$

$F_y = 200.7 N$

so 200.7 N is not used to find out work done