Answer:
Option B is correct.
Reason:It is an argument
Step-by-step explanation:
Given: [tex]AB \cong BC[/tex] and [tex]BC \cong EF[/tex]
By transitive property: a = b and b = c then, a =c
⇒[tex]AB \cong EF[/tex]
AB = EF [def of [tex]\cong[/tex] segment]
By Segment Addition Postulate states that given two points A and C, and a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation
AB + BC = AC.
Since, the line segment EG , F lies on the line segment;
then, by segment addition postulates we have;
EG = EF + FG
By substitution AB=EF
⇒ EG = AB + FG hence proved!
Since, in the fourth statement reason is: It is an argument