Question

given RST = NPQ R=-7x+9, N=-10x find R and N

Answer 1

Answer:

$m\angle N=m\angle R=30^{\circ}$

Step-by-step explanation:

We are given that

$\triangle RST=\triangle NPQ$

$m\angle R=-7x+9,m\angle N=-10x$

We have to find the measure of angle R and measure of angle N.

When two triangles are equal then their angles are equal

Therefore, $m\angle R=m\angle N$

$-7x+9=-10x$

$-7x+10x=-9$

By subtraction property of equality

$3x=-9$

By combine like terms

$x=\frac{-9}{3}=-3$

By division property of equality

Substitute x=-3 then we get

$m\angle R=-7(-3)+9=21+9=30^{\circ}$

$m\angle N=m\angle R=30^{\circ}$

Answer 2

Answer:

30

Step-by-step explanation: