Question

What is the equation of the line with a slope of -2 that passes through the

point (4, -3)?

y + 3 = 4(x - (-2))
y + 4 = -2(x - 3)
y + 3 = -2(x - 4)
y + 4 = 3(x - (-2))

Answer 1

The point-slope form of the line:

$y-y_1=m(x-x_1)$

We have the slope m = -2 and the point (4, -3). Substitute:

$y-(-3)=-2(x-4)\\\\\boxed{y+3=-2(x-4)}$