Question

In the diagram below, a student compresses the spring in a pop-up toy a distance of 0.020 m. If 0.068 J of energy are stored in the toy, what is the toy’s spring constant? a) 120 N/m b) 170 N/m c) 225 N/m d) 340 N/m

Answer 1

Answer: option d) 340 N/m

Explanation:

Energy stored in the spring of the toy,

$E = \frac{1}{2}kx^2 = 0.068 J$  ( given)

Where, k is the spring constant and x is the length of the string after compression.

x = 0.020 m

Then spring constant, $k = \frac{2E}{x^2}$

$k = \frac{2\times 0.068 J}{(0.020 m)^2} = 340 N/m$

Thus, the spring constant of toy is 340 N/m. Correct option is d.

Answer 2

The stiffness of the spring depends on the spring constant. Fo higher the spring constant, the more difficult it is to stretch.

The spring constant of the spring of a pop-up toy is 340 N/m.

What is the spring constant?

The spring constant, k, is a measure of the stiffness of the spring. The larger the spring constant, the stiffer the spring.

Given that the energy stored in the toy is 0.068 to stretch a spring at a distance of 0.020 m.

The energy stored in the toy is given as,

$E = \dfrac {1}{2} kx^2$

Where E is the energy and x is the distance.

$0.068 = \dfrac {1}{2} k \times 0.020^2$

$k = 340\;\rm N/m$

Hence we can conclude that the spring constant is 340 N/m.

To know more about the spring constant, follow the link given below.

https://brainly.com/question/4291098.