Question

Write a chemical equation representing the third ionization energy for lithium. use eâ as the symbol for an electron

Answer 1

$\text{Li}^{2+} \; (g) \to \text{Li}^{3+} \; (g)+ \text{e}^{-}$

Explanation

Ionization energy is what it takes to free one mole of electrons from one mole of gaseous atoms or ions.

The first ionization energy takes electrons away from a neutral atom. The atom here has to be gaseous.

$\text{Li}^{} \; (g) \to \text{Li}^{+} \; (g)+ \text{e}^{-}$

The second ionization energy removes one electron from the $\text{Li}^{+}$ ion. The ion shall also be gaseous.

$\text{Li}^{+} \; (g) \to \text{Li}^{2+} \; (g)+ \text{e}^{-}$

Removes one more electron. Doing so will convert the $\text{Li}^{2+} \; (g)$ ion to a gaseous $\text{Li}^{3+}$.

$\text{Li}^{2+} \; (g) \to \text{Li}^{3+} \; (g) + \text{e}^{-}$.

The process above removes the third electron from lithium. Its energy change is the third ionization energy of this element.

Answer 2

The chemical equation representing the third ionization energy for lithium is;

$Li^{2+} + e^{-} -----> Li^{3+}$

Ionization is the loss of electrons. The energy required for electrons to be lost is called the ionization energy.

For an atom having n electrons, there can be n number of ionization energies as electrons are successively lost from the atom.

The equation showing the third ionization energy of lithium has been shown above.

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