Question

4. Find the length of AB if A is located (-2,0) and B is located at (5,0)

5. If EF=9x+14, FG=56, and EG=250, find the value of x. The drawing is not to scale.

Answer 1

Answer: 4. 7 unit

5. 20 unit

Step-by-step explanation:

4. Since, A≡ (-7,0) and B≡ (5,0)

Thus, By the distance formula,

$AB = \sqrt{(5-(-2))^2+ (0-0)^2}$

⇒ $AB = \sqrt{(5+2)^2+ (0)^2}$

⇒ $AB = \sqrt{(7)^2+ (0)^2}$

⇒ $AB = \sqrt{49+0}$

⇒ $AB = \sqrt{49}$

⇒ AB = 7 unit

5. Here EF = 9x + 14, FG = 56 and EG= 250

But, According to the given diagram,

EF + FG = EG ( because G divides the line EG )

⇒ 9x + 14 + 56 = 250

⇒ 9x + 70 = 250

⇒ 9x = 250 - 70 ( By subtracting both sides by 70)

⇒ 9x = 180

⇒ x = 20  ( by dividing both sides by 9 )

Thus, the value of x is 20.

Answer 2

idk but if anyone took the geometry semester exam.

If you have for number 5 : If JK =6r, KL=3r, and JL=27,  what is the value of r?