Answer:
The tension force in the supporting cables is 7245N
Explanation:
There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:
[tex]F_{net} = F_g - F = m\cdot g - F\\[/tex]
We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:
[tex]1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N[/tex]
The tension force F in the supporting cables is 7245N
