Answer:
Jeff had in the account 3,623.85 after 3 years
Step-by-step explanation:
Investment: p=3,000
Interest: i=6.5%=6.5/100→i=0.065
Time (in years): t=3
A(3)=?
A(t)=p(1+i)^t
t=3→A(3)=p(1+i)^3
Replacing the given values:
A(3)=3,000 (1+0.065)^3
A(3)=3,000 (1.065)^3
A(3)=3,000 (1.207949625)
A(3)=3,623.848875
Rounding to the nearest hundredth:
A(3)=3,623.85