Answer: (2, 9)
Step-by-step explanation:
[tex]\lbrace^{y=5x-1 }_{2y=3x+12}}[/tex]
Since "y" = "5x - 1", we can replace "y" in the second equation with "5x - 1"
2y = 3x + 12
⇒ 2(5x - 1) = 3x + 12 substituted "y" with "5x - 1"
⇒ 10x - 2 = 3x + 12 distributed 5x - 1 by 2 on left side
⇒ 7x - 2 = 12 subtracted 3x from both sides
⇒ 7x = 14 added 2 to both sides
⇒ x = 2 divided both sides by 2
Next, let's solve for y by substituting "x" with "2":
y = 5x - 1
= 5(2) - 1
= 10 - 1
= 9
