Question

What is the equation of the graph below? A graph shows a parabola that opens up and crosses the x axis at negative two and negative four. y = − (x − 3)2 + 1 y = − (x + 3)2 + 1 y = (x − 3)2 − 1 y = (x + 3)2 − 1

Answer 1

Answer:

$y=(x+3)^{2} -1$

Step-by-step explanation:

General equation of a parabola that opens up is $y=a(x-h)^{2} +k$ , a>0

So equation becomes $y=(x-h)^{2} +k$ which implies option A and option B can never be true for this parabola.

Also this parabola's vertex lies in 3rd quadrant where coordinates of both x and y will be negative.

So, the equation of parabola will be of the form $y=(x+h)^{2} - k$

Hence, option 4 that is $y=(x+3)^{2} -1$ is correct.

Answer 2

Answer:

y = (x+3)^2 - 1

Step-by-step explanation: