Answer:
[tex]x=2.8[/tex]
Step-by-step explanation:
we are given that
line passes through (2,-1) and (6,4)
Firstly, we will find equation of line
First point is (2,-1)
x1=2, y1=-1
second point is (6,4)
x2=6 , y2=4
now, we can find slope
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
now, we can plug values
[tex]m=\frac{4+1}{6-2}[/tex]
[tex]m=\frac{5}{4}[/tex]
now, we can use point slope form of line
[tex]y-y_1=m(x-x_1)[/tex]
now, we can plug values
[tex]y+1=\frac{5}{4}(x-2)[/tex]
since, we have to solve for x from (x,0)
so, we can set y=0
and then we can solve for x
[tex]0+1=\frac{5}{4}(x-2)[/tex]
[tex]5\left(x-2\right)=4[/tex]
[tex]x-2=\frac{4}{5}[/tex]
[tex]x=\frac{14}{5}[/tex]
[tex]x=2.8[/tex]