Question

A room is 20 feet long, 12 feet wide, and 10 feet high. What is the maximum distance from one corner to another

Answer 1

Answer:

25.38

Step-by-step explanation:

Its a 3-D block, so you have to find the distance from on corner to the opposite corner of the roof, but first find the distance from corner to corner on the floor.

20^2+12^2=c^2

400+144=544=c^2

c=$\sqrt{544}$

then find corner of floor to opposite roof corner.

100+544=644=c^2

c=$\sqrt{644}$

so its about 25.38 feet

Answer 2

Answer:

25.4 ft  

Step-by-step explanation:

Let D1 be the distance from one corner to the diagonally opposite one and D2 be the  diagonal distance from one corner to the ceiling.

D1² = 20² + 12²

D2² = D1² + 10²            Substitute the value of D1²

D2² = 20² + 12² + 10²

D2² = 400 + 144 + 100

D2² = 644

D2 = √(644)

D2 = 2√(161)

D2 ≈ 25.4 ft