janice buys 74 packs of gum in a variety of flavors. she chooses twice as many packs of green apple gum as packs of spearmint gum and 6 fewer packs of cinnamon gum that packs of green apple gum. How many packs of spearmint gum does janice buy?
![janice buys 74 packs of gum in a variety of flavors she chooses twice as many packs of green apple gum as packs of spearmint gum and 6 fewer packs of cinnamon g class=](https://us-static.z-dn.net/files/de9/9adeb6571c166953f1c2bb5b41d6f732.png)
Answer:
A) 16
Step-by-step explanation:
g= green apple
c= cinnamon
s= spearmint
74=g+c+s
g=2s
g-6=c
so we can replace c in the equation
74=g+g-6+s (because c=g-6)
we can also replace g in the equation
2s+2s-6+s=74 (because g=2s)
so, 5s-6=74 (add 6 to both sides)
5s=80 (divide by 5)
s=16
Answer: Hello there!
Let's define G has the number of packs of green apple, S as the number of packs of spearmint, and C as the number of packs of cinnamon.
Now we want to know the number of spearmint gum packs that Janice buys:
We know that:
G + S + C = 74
G = 2S
G - C = 6
Now we have a system of 3 equations and 3 variables, let's solve it.
In the second equation we can remove G of the equations, and replace it in the first and third equation:
G + S + C = 74
2S + S + C = 74
3S + C = 74
and
G - C = 6
2S - C = 6
Now we only have two equations, lets isolate C in the second equation
2S - C = 6
C = 2S - 6
now we can replace it in the first equation, and solve it for S
3S + C = 74
3S + 2S - 6 = 74
5S = 74 + 6 = 80
S = 80/5 = 16
She buy's 16 packs of spearmint gum.