The length of s and hypotenuse
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Answer:
A
Step-by-step explanation:
this is a standard right triangle 30-60-90
with legs 1 and [tex]\sqrt{3}[/tex] and hypotenuse 2, hence
s = [tex]\sqrt{3}[/tex] and h = 2
Answer:
A. [tex]\sqrt{3}[/tex] ; 2
Step-by-step explanation:
Since We have all the angles of the triangle and one side we can use SIN, COS, and TAN to find the missing side lengths. SIN which is [tex]sin(x) = \frac{opposite}{hypotenuse}[/tex] can be used to find the hypotenuse
[tex]sin(30) = \frac{1}{h}[/tex]
[tex]\frac{1}{sin(30)} = \frac{h}{1}[/tex] ..... inverse both sides
[tex]\frac{1}{sin(30)} = h[/tex]
[tex]2 = h[/tex]
Now we can use the Pythagorean theorem to find the missing length. The Pythagorean Theorem is [tex]a^{2} +s^{2} = h^{2}[/tex]. So we just plug in the values we already have and solve for s.
[tex]1^{2} +x^{2} = 2^{2}[/tex]
[tex]1+s^{2} = 4[/tex]
[tex]s^{2} = 3[/tex]
[tex]s = \sqrt{3}[/tex]
In Conclusion, s = [tex]\sqrt{3}[/tex] and h = 2
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