Question

A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773 what is the weight of the box?

Answer 1

Given Data:

mass (m) = 50 Kg

W = m*g = 50×9.81 = 490.5 N

Coefficient of static friction (μs) = 0.5773

ramp angle = 30 degrees

determine Normal force=?

From the figure we know that

Normal force (N) = μs.W cosΘ

                           = 0.5773 ×490.5×cos 30

                           = 245.22 N

Therefore, The Normal force = 245.23 N