Answer:
Consider the given figure.
Given: [tex]\angle A=\angle D[/tex]
To prove: [tex]\Delta ACB \sim \Delta DCE[/tex]
Proof:
Statements Reasons
1. [tex]\angle BCA = \angle DCE[/tex] Vertically opposite angles
2. [tex]\angle A = \angle D[/tex] given
Hence, the given triangles are similar by AA similarity criteria as "AA criterion for triangle similarity states that if two triangles have two pairs of congruent angles, then the triangles are similar".
