Answer:
3.99 kg
Explanation:
The period of a harmonic oscillator is given by:
[tex]T=2 \pi \sqrt{\frac{m}{k}}[/tex]
where
m is the mass attached to the spring
k is the spring constant
In this problem, we know:
k = 712 N/m
T = 0.47 s
Therefore, we can re-arrange the equation to find the mass that should be attached to the oscillator:
[tex]m=\frac{k T^2}{(2 \pi)^2}=\frac{(712 N/m)(0.47 s)^2}{(2 \pi)^2}=3.99 kg[/tex]
