ANSWER
The equation of the given line is
[tex]4y - 3x + 18 = 0[/tex]
EXPLANATION
The line passes through the points
[tex](2,-3) \: and \: ( - 2,-6)[/tex]
We can use these two points to determine the slope as follows:
[tex]slope = \frac{ - 6 - - 3}{ - 2 - 2} [/tex]
[tex]slope = \frac{ - 6 + 3}{ - 2 - 2} [/tex]
[tex]slope = \frac{ -3}{ - 4} = \frac{3}{4} [/tex]
We now apply the point slope formula
[tex]y-y_1=m(x-x_1)[/tex]
to obtain,
[tex]y + 3 = \frac{3}{4} (x - 2)[/tex]
We multiply through by 4 to get,
[tex]4y + 12 = 3(x - 2)[/tex]
This gives us,
[tex]4y + 12 = 3x - 6[/tex]
We simplify further to get,
[tex]4y - 3x + 18 = 0[/tex]