If GF is a midsegment of CDE, find CD.
A. 3.4
B. 6.8
C. 13.6
D. 14
![If GF is a midsegment of CDE find CD A 34B 68 C 136 D 14 class=](https://us-static.z-dn.net/files/d6d/7c765477fbb14d76569279b12e689208.png)
Answer:
C
Step-by-step explanation:
Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:
[tex]\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}[/tex]
We can now cross multiply and solve for CD:
[tex]\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}[/tex]
Since GF is a midsegment of CDE, CD is double of CF. So we can write:
[tex]CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0[/tex]
By using quadratic formula [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex] and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:
[tex]\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2[/tex]
Since the expression for CD is [tex]\frac{15x^2+16x+3.2}{2x+3}[/tex] , we plug in [tex]x=2[/tex] into this expression to find value of CD:
[tex]\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6[/tex]
The correct answer is C
Answer:
C. 13.6
Step-by-step explanation:
We have been given that GF is a mid-segment of CDE.
Since we know that mid-segment of a triangle is half the length of its parallel side.
We can see that ED is parallel to GF , so measure of GF will be half the measure of ED. We can represent this information as:
[tex]GF=\frac{1}{2}ED[/tex]
Let us substitute given value of GF and ED to find our x.
[tex]2x+3=\frac{1}{2}(5x+4)[/tex]
Multiply both sides of equation by 2.
[tex]2*(2x+3)=2*\frac{1}{2}(5x+4)[/tex]
[tex]2*(2x+3)=5x+4[/tex]
[tex]4x+6=5x+4[/tex]
[tex]6=5x+4-4x[/tex]
[tex]6=x+4[/tex]
[tex]6-4=x[/tex]
[tex]2=x[/tex]
We can see that triangle CFG is similar to triangle CDE, so we will use proportions to find length of CD.
[tex]\frac{CF}{GF}=\frac{CD}{ED}[/tex]
Substitute given values.
[tex]\frac{3x+0.8}{2x+3}=\frac{CD}{5x+4}[/tex]
Upon substituting x=2 in our equation we will get,
[tex]\frac{3*2+0.8}{2*2+3}=\frac{CD}{5*2+4}[/tex]
Let us simplify our equation.
[tex]\frac{6+0.8}{4+3}=\frac{CD}{10+4}[/tex]
[tex]\frac{6.8}{7}=\frac{CD}{14}[/tex]
[tex]14*\frac{6.8}{7}=CD[/tex]
[tex]2*6.8=CD[/tex]
[tex]13.6=CD[/tex]
Therefore, CD equals 13.6 and option C is the correct choice.