Answer:
The focii are 8 feet apart
Step-by-step explanation:
You can use the formula
F = √(a^2 - b^2) where F is the distance of the focii from the center , a = length of the semi major axis and b = length of the semi minor axis)
So here it is √(5^2 - 3^2)
= √16 = 4
So the distance is 2*4 = 8
Quadratic relations and comic sections unit test part 1
12. b. 8 feet
1. b ellipse
domain -4<=x<=4
range -3<=y<=3
2. c. x^2/3
3. c. 1/10 x^2
4. b. 5 inches
5. d. x=1/12 (y-4)^2 +2
6. b. (x-4)^2 + (y-5)^2 =49
7. b. (x+8)^2 + (y+4)^2 =25
8. d. (x+3)^2 + (y+2)^2 =9
9. a. center at (7,-6); radius 4
10. b. x^2/25 + y^2/169 =1
11. a. (0, +/- 6)
12. b. 8 ft
13. c. (put equation in graphing calculator to see graph)
14. d. (0, +/-5)
