Answer:
2.0 J
Explanation:
Since the surface is frictionless, we can solve the problem by using the work-energy theorem, which states that the work done on the toy is equal to the kinetic energy gained by the toy:
[tex]W=\Delta E_k[/tex]
where
W is the work done on the toy
[tex]\Delta E_k[/tex] is the kinetic energy gained by the toy
The work done can be calculated as the product between the force applied on the toy and its displacement, so:
[tex]W=Fd=(2.0 N)(1.0 m)=2.0 J[/tex]
Therefore, according to the work-energy theorem, the toy has gained 2.0 J of kinetic energy.
Answer: 2 J
Explanation: Kinetic energy is possessed by a body due to virtue of its motion. A body gains kinetic energy when some work is done on it.
W = Δ K.E.
We know that work is said to be done on a body when a force causes displacement of the body.
W = F.s
It is given that net force on the toy, F = 2.0 N which displaces the toy by, s = 1.0 m.
Hence, work done on the toy, W = 2.0 N × 1.0 m = 2 J which is equal to the kinetic energy gained by the toy.
