Question

Please help me. Explanation needed in algebraic form:
A painting, square in shape, is placed in a wooden frame with width of 10% of the length of the side of the painting. The painting was enlarged by 10%. By what percent is the new frame bigger than the original frame if the width of the frame remains the same?

Answer 1

Answer:

the new frame is bigger than the original frame by 10%

Step-by-step explanation:

Let the length of the original frame be l,

then it's width is (10% of l)=$\frac{10}{100}$×l

                                           =$\frac{l}{10}$

hence area of original frame=A=length×width

                                               =$\frac{l^{2} }{10}$

now the length of frame is enlarged by 10%

new lenght of frame=l+10%×l

                                 =l+$\frac{10}{100}$×l

                                  =$\frac{11}{10}$×l

width of new frame==$\frac{l}{10}$

area of new frame=length×width

                              =$\frac{11l^{2} }{100}$

percent change=((area of new frame-area of old frame)×100)÷area of old frame

=10%

Answer 2

Answer:

9.09091%

Step-by-step explanation: