Answer:
Domain of y=[tex]\sqrt[4]{x-1}[/tex]: is x>=1
Interval notation: [1,∞)
Step-by-step explanation:
We have y=[tex]\sqrt[4]{x-1}[/tex]
1) The domain of a function is the set of x values for which the function is real and defined.
2) So, x-1 should be positive means x-1>=0, because fourth root of any negative value would be a complex number and not a real number.
3) Now we solve the inequality x-1>=0
4) Adding 1 to both sides of the inequality we get,
x-1+1 > = 0+1
5) Cancel out -1 and +1 from the left side
6) We get x>=1
It concludes that for the domain of the given function, the x value must be greater than or equal to 1
