Question

the force needed to lift a 3000 N truck using a jack with a MA of 15

Answer 1

As we know that mechanical advantage is defined as

$MA = \frac{F_o}{F_{in}}$

now here we have

$MA = 15$

also we have

$F_O = 3000 N$

now we will have

$15 = \frac{3000}{F_{in}}$

now we will have

$F_{in} = \frac{3000}{15}$

$F_{in} = 200 N$

so our applied force will be 200 N